Question

A 10 mF, 20 mF, 25 mF, and 100 mF capacitor are in parallel. The total
capacitance is

O 0.2 mF
O 5 mF
O 100 m
O 155 mF​

Answer 1

Answer:

155mF

Explanation:

C =10+20+25+100=155mF

Answer 2

Answer:

The answer is 155mF

Explanation:

As we all know, capacitance is the amount of separated electric charge that may be stored on an electric conductor or set of conductors per unit charge in electric potential. Capacitors are often used to store energy.

The equation for total capacitance when capacitors $C_1, C_2, C_3$ and $C_4$ are connected in parallel = $C_1+C_2+C_3+C_4$

In this question, the given information is as follows

$C_1$=10mF $C_2$=20mF $C_3$=25mF $C_4$=100mF

Therefore the total capacitance C=$C_1+C_2+C_3+C_4$

                                                    = 10+20+25+100  = 155mF

Hence the total capacitance is 155mF