A 10 mm long awl pin is placed vertically in front of a concave mirror. A 5 mm long image of the awl pin is formed at 30 cm in front of the mirror. The focal length of this mirror is ?
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Answer:
We have,
f
1
=
v
1
+
u
1
Also,
m=
u
v
=
x
−y
Where,
y is image height
and x is object's height.
We have,
x=10 and y=−5
Also, v=30
∴u=60
Now, using mirror's formula:
f
1
=
30
1
+
60
1
∴f=20 cm
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