Question

A 10-ohm resistor has a constant current. If 1200 C of charge flow through it in 4 minutes what is the value of the current?

Answer 1

Answer:

B 5.0 A.

Explanation:

In this case, since we know the charge (1200 C), time (4 min =240 s) and resistance (10Ω) which is actually not needed here, we compute the current as follows:

I=Q/t

Q= 1200C. and t= 4*60=240 second.

Then, for the given data, we obtain:

I=1200/240

Then, answer is B 5.0 A .

Answer 2

Answer:

The answer is 5.0 A.

Explanation:

i) Given data:

Charge (Q) = 1200 C

Time (t) = 4 min = 240 s

Resistance (R) = 10 Ω

ii) Using the following formula:

I = Q/t

We can compute I as:

I = 1200/240 = 5 A

iii) Hence, the value of current is 5.0 A.

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