A 10 omega thich wire is stretched so that its lenght become 3 times . assuming that there is no change in its density in stretching , calculate the resistance at the new wire.
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Explanation:
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Answer:- 90 ohms
Explanation:-
Initial length of wire ,L1 = l
Final length of wire L2= 3l
Initial resistance of wire is R1= 10 ohms (given)
Final resistance = ? (R2)
W.K.T,
R Is directly proportional to l^2
=> R2/R1=(L2/L1)^2 = (3l/l)^2 = 9
R2 = 9R1
=> 9*10 = 90 ohms.
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