Question

a 10 resistance is connected in series with a cell of emf 10v. A voltmeter is connected in parallel to a cell, and it reads. 9.9 v. Find internal resistance of the cell.

Answer 1

Answer:

Since, two V in parallel, so net V in circuit = 10-9.9 = 0.1V

Again since it's a parallel connection, so current= 9.9/10= 0.99A

So, internal resistance= 0.1/0.99 = 0.101 ohm