Question

A 10’s place digit of 2 digit number is thrice its unit place the no obtained by interchanging digits is less than original number by 54 find the original number

Answer 1

$\huge{\underline{\bf{\blue{Question:-}}}}$

A 10’s place digit of 2 digit number is thrice its unit place the no obtained by interchanging digits is less than original number by 54 find the original number.

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$\large{\underline{\bf{\pink{Answer:-}}}}$

✰ The original number is 93.

$\large{\underline{\bf{\purple{Explanation:-}}}}$

$\large{\underline{\bf{\green{Given:-}}}}$

✰ 10th place digit = thrice it's unit digit.

✰ the no obtained by interchanging digits is less than original number by 54.

$\large{\underline{\bf{\green{To\:Find:-}}}}$

✰ we need to find the original number.

$\huge{\underline{\bf{\red{Solution:-}}}}$

Let the one's place digit be x

so , the tenth place digit is 3x

Then,

The number = 10( 3x ) + x

⠀⠀⠀⠀⠀⠀⠀⠀= 31x

Now,

⠀⠀⠀⠀⠀If we interchanging digits

So ,

The new number formed = 10x + 3x

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 13x

Now,

${\pink{\bf{\underbrace{According\:to\: question}}}}$

New Number is less than 54 from the old Number.

31x - 54 = 13x

$:\implies$31x - 13x = 54

$:\implies$ 18x = 54

$:\implies$ x = 54/18

$:\implies$ x = 3

So the number is 10×3×3+3 = 93.

∴ The original number is 93.

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Answer 2

Solutions:

Let the one's place digit be x

so, the tenth place digit is 3x .

then, the number = 10(3x) + 4

Now, we interchanging digits

so, the number form = 10x + 3 = 13x

A.T.Q

new number is less than 54 form the old number.

31x - 54 = 13x

31x - 13x = 54

18x = 54

x = 54/18

x = 3

so. the no. is 10 + 3 × 3 + 3

= 93.

silentlover45.❤️