Question

A 10 solution by mass of sucrose in water has freezing point of 269.15k calculate the freezing point of10% solution glucose in water if the freezing point of pure water is 273.15k

Answer 1

I tried to answer but I can't

Answer 2

Answer: T1=269.15K

T2=273.15K

mm of sucrose=342gmol-1

mm of glucose=180gmol-1

10% soln means 10g out of 100g i.e 100-10=90g (solvent w2)

ΔTf=Kfm

now, m= w2*1000/M2*w1

273.15-269.15=Kf*10*1000/342*90

                       Kf=12.3Kkg/mol

    ΔTf=Kfm

=12.3*10*1000/180*90

=7.6K

Tf=273.15-7.6=26.55K                      

hope it helps.........

Explanation: