Question

A 10 turn closely wound circular coil of radius 10 cm carries a current of 3.2 A. What is the magnetic moment of this coil? *​

Answer 1

Answer:

Explanation:

Given data states that the number of turn as n = 100 and the current I is 3.2 A with radius of the coil being r = 10 cm which is 0.1 m. therefore to find the magnetic field at centre of the coil, we simply need to put the given values in to Magnetic field formula, which is

B = μoni/2r => B = (4p × 10-7 × 100 × 3.2)/2 × 0.1 => B = 2 x 10-³T.

And similarly for the Magnetic moment of the coil, simply input the answer into

M ni A

=> M ni x pr² 100 × 3.2 x 3.14 x 0.1 x 0.1 => M = 10 Am²