A 10 uF capacitor is connected with 100 V battery. What would be the clectrostatic energy stored?
Answers
Answered by
2
Answer:
0.05J
Explanation:
E=1/2CxV^2
C=10microfarad=10x10^-6=10^-5
V^2=100V^2=10^4
therefore
E=1/2[10^-5×10^-4]
=1/2 × 1/10
=1/20
=0.05
Similar questions