Question

A 10 v battery if negligible internal resistance is charged by a 200 V dc supply. If the resistance in the charging circuit is 38 ohm , what is the value of charging current?

Answer 1

Given,

V 1 = 10 V

V 2 = 200 V

As the battery emf opposes the charge emf,

Thus the net emf = V 2 - V 1

                             =  200 V - 10 V

                            = 190 V

and ,

we know I = $\frac{net emf}{resistance}$

here , resistance  is 38 ohm

Charging current = I = $\frac{net emf}{resistance}$

                                  =  198 V / 38 Ohm

                                   = 5 A

∴ The value of charging current is 5 A.

Answer 2

$\huge{\mathfrak{solution:-}}$

Let i be the current flowing in the circuit

By Kirchhoff's law,

38i =200 - 10

⇒ i = 190/38

⇒ i = 5 A.

Note:- Kirchhoff's law explained in attachment file.