A 10 V battery of negligible internal resistance is charged by 120V d.c. supply. If the resistance in the circuit is 22 ohm, the value of charging current is: (A)12 A (B) 10A (C) 5A (D) 2.2 A
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Explanation:
The net potential difference applied across the resistor=200V−10V=190V
The resistance of the resistor=38Ω
Hence current through the resistor=
38Ω
190V
=5A
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