A 10 v cell of negligible internal resistance is connected in parallel across a battery of EMF 200 v and internal resistance 38 ohm as shown in the figure find the value of current in the circuit
Answers
Answered by
18
★★
հίί ʍαtε_______✯◡✯
.
.
.
.
_________________________
һєяє' ʏȏȗя ѧṅśwєя ʟȏȏҡıṅɢ ғȏя________
.
✯^_^very easy question,
♦Let i be the current flowing in the circuit,
▶By Kirchhoff’s law
》38i = 200 – 10
=> i = 190/38
=> i = 5A
A
____________________★
★BRAINLY★
հίί ʍαtε_______✯◡✯
.
.
.
.
_________________________
һєяє' ʏȏȗя ѧṅśwєя ʟȏȏҡıṅɢ ғȏя________
.
✯^_^very easy question,
♦Let i be the current flowing in the circuit,
▶By Kirchhoff’s law
》38i = 200 – 10
=> i = 190/38
=> i = 5A
A
____________________★
★BRAINLY★
Attachments:
Answered by
1
Let i be the current flowing in the circuit,
▶By Kirchhoff’s law
》38i = 200 – 10
=> i = 190/38
=> i = 5A
so \: the \: value \: of current \: is \: 5sothevalueofcurrentis5 A
Similar questions