Question

A 10 watt bulb emits yellow light of wavelength 0.4um. Calculate rate of emission of quanta per

second.​

Answer 1

Explanation:

The energy of one photon is

E=

λ

hc

=

0.57×10

−6

6.626×10

−34

Js×3×10

8

m/s

=3.487×10

−19

J .

25 watt corresponds to 25 J per second.

The number of photons emitted per second is

3.487×10

−19

25

=7.17×10

19

/s.

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