a(10-x)-(10-x) factorise it please
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Rearrange terms
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a({\color{#c92786}{10-x}})-(10-x)
a(10−x)−(10−x)
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a({\color{#c92786}{-x+10}})-(10-x)
a(−x+10)−(10−x)
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Distribute
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{\color{#c92786}{a(-x+10)}}-(10-x)
a(−x+10)−(10−x)
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{\color{#c92786}{-ax+10a}}-(10-x)
−ax+10a−(10−x)
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Rearrange terms
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-a \cdot x+10a-({\color{#c92786}{10-x}})
−a⋅x+10a−(10−x)
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-a \cdot x+10a-({\color{#c92786}{-x+10}})
−a⋅x+10a−(−x+10)
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Distribute
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-a \cdot x+10a-\left(-x+10\right)
−a⋅x+10a−(−x+10)
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-a \cdot x+10a+x-10
−a⋅x+10a+x−10
Solution
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