Question

A 100.0 g brass block at 100.0ºC is placed in 200.0 g of water at 20.0ºC. The specific heat of brass is 376 J/kg•ºC. Assuming no heat loss to the surroundings, what is the final temperature of the mixture?

Answer 1

Explanation:

principle of calorimeter

heat lost = heat gained

heat lost by brass = heat gained by water

100 /1000 x 376 x (100 - T)= 200/1000 x 1 x (T-20)

0.1 X 376 X (100-T) = 0.2 X (T-20)

3760 - 37.6T = 0.2T -4

3760+4 = 0.2T + 37.6T

3764 = 37.8 T

T = (3764/37.8)⁰C =99.5⁰C