Question

(a) 100

A brick of mass 2kg is dropped from rest position 12m above the ground. At height 7m above
ground its velocity is:
(a) 49ms
(b) 7ms
(c) 12ms
(d) 10ms
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Answer 1

Answer:

The velocity of brick at height of 7m above ground will be 9.899m/s

Explanation:

$a= 9.8 m/s^{2} \\m= 2kg\\s= (12-7)m=5m\\u=0m/s^{2} \\\\now using the formula\\v^{2} = u^{2} + 2as\\\\v^{2}= 2*9.8m/s^{2}*5m\\v=\sqrt{98m^{2}/s^{2} } \\v= 9.899 m/s$

I hope it helps you.

Answer 2

Answer:

Explanation:

(a) 49ms