a 100 cm3 block has a massof 395 g . find its relative density
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given v=100cm^3 m=395g
Density ofthe substance D=m/v
D= 395/100
D=3.95g/cc
Relative density =density of the substance / density of water
(density of water=1g/cc) cc-cubic centimeter
relative density =3.95/1
So relative density =3.95.
Density ofthe substance D=m/v
D= 395/100
D=3.95g/cc
Relative density =density of the substance / density of water
(density of water=1g/cc) cc-cubic centimeter
relative density =3.95/1
So relative density =3.95.
Answered by
3
Answer:
Given v=100cm^3 m=395g
Density ofthe substance D=m/v
D= 395/100
D=3.95g/cc
Relative density =density of the substance / density of water
Relative density =3.95/1
So relative density =3.95.
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