a 100 g mass moving at 6 m/s collides with another 100 g mass at rest, find the velocity of second mass after the collision ,if the first comes to rest.
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mass of object 1, m1= 100 g
initial velocity of object 1, u1= 6 m/s
final velocity of object 1, v1= 0 m/s
mass of object 2, m2= 100 g
initial velocity of object 2, u2= 0 m/s
final velocity of object 2, v2= ?
From the law of conservation of momentum, we have
total initial momentum = total final momentum
m1u1 + m2u2 = m1v1 + m2v2
⇒ 100 g × 6 m/s + 100 g × 0 m/s = 100 g × 0 m/s + 100 g × v2
⇒ 600 gm/s + 0 gm/s = 0 gm/s + 100g × v2
⇒ 600 gm/s = 100g ×v2
⇒ 6 m/s = v2
⇒ v2 = 6m/s
Therefore, the velocity of second mass after the collision is 6 m/s .
initial velocity of object 1, u1= 6 m/s
final velocity of object 1, v1= 0 m/s
mass of object 2, m2= 100 g
initial velocity of object 2, u2= 0 m/s
final velocity of object 2, v2= ?
From the law of conservation of momentum, we have
total initial momentum = total final momentum
m1u1 + m2u2 = m1v1 + m2v2
⇒ 100 g × 6 m/s + 100 g × 0 m/s = 100 g × 0 m/s + 100 g × v2
⇒ 600 gm/s + 0 gm/s = 0 gm/s + 100g × v2
⇒ 600 gm/s = 100g ×v2
⇒ 6 m/s = v2
⇒ v2 = 6m/s
Therefore, the velocity of second mass after the collision is 6 m/s .
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