Question

A 100 grams bullet is fired from a 10 kg gun with a speed of 1000 m/s. What is the speed of recoil of the gun​

Answer 1

Answer:

It can be found using the relation as

p=mv

where,

p=momentum

m=mass=10kg=0.01g (Divide by 1000)

v=velocity=1000m/s

so,

P=(0.01)(1000)

p=10kgm/s

MARK AS BRAINLIEST :D

Answer 2

Answer:10m/s

Explanation: m¹v¹=m²v²

Where m¹ and v¹ are mass and velocity of the bullet respectively

And m² and v² are the mass and velocity of the gun also

Therefore 0.1×1000=10×v²

100=10v

V=10m/s