Question

A 100 k-w is operating between 217 degree celcius and 17 degree Celsius calculate the amount of heat absorb and amount of heat rejected and the efficiency of the engine

Answer 1

Answer:

Explanation:

Efficiency (₩) =work done/heat=W/Q

Also ₩=1- (T2/T1)

Therefore W/Q=1 -(T2/T1)

None of heat and work is given?

Because I can't proceed further