Question

a 100 kg man stands in a lift what force does the floor exert on him when the lift starts moving upward with an acceleration of 2 m by a square when grams is equal to 10 m/s^2

Answer 1

Answer:

The formula that help in it is f =ms

Explanation:

so do it

Answer 2

Acc. To me,

Your answer is 1200N

When man on lift then

The lift only exerts Normal force because of man weight

When you draw Free body Diagram

then N is upward and mg is downward and no other force is there

and instead of this man accelerate in lift move upward with 2m/sec²

So

F net=ma

N-mg=ma

N=ma+mg

N=m(a+g)

N=100(2+10)

N=100(12)

N=1200Newton