Question

a 100 kg man went jogging here on at the rate of 6 m/s how much kinetic energy did he have?​

Answer 1

Explanation:

m = 100 kg

v = 6 m/s

K.E = $\frac{1}{2} mv^{2}$

= $\frac{1}{2}$ × 100 × $6^{2}$

= 50 × 36

= 1800 joules

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