Math, asked by zoozbarakat, 4 months ago

a 100 kg mixture of two different types of nuts costa $550. if type A costs $4 per kg and type B costs $7 per kg, how many of each type were used?

Answers

Answered by bhagyashreechowdhury
0

Given:

A 100 kg mixture of two different types of nuts costa $550.

If type A costs $4 per kg and type B costs $7 per kg

To find:

How many of each type were used?

Solution:

Let's assume,

"x" kg → represents the quantity of type A used

"y" kg → represents the quantity of type B used

The total quantity of the mixture of nuts used = 100 kg

x + y = 100 ...... (i)

Type A costs $ 4 per kg, type B costs $ 7 per kg and the total cost of the mixture $ 550

4x + 7y = 550 .... (ii)

On multiplying eq. (i) by 4, we get

4x + 4y = 400 ..... (iii)

On subtracting eq. (iii) from eq. (ii), we get

4x + 7y = 550

4x + 4y = 400

-    -          -

---------------------

  3y = 150

----------------------

\bold{y}  = \frac{150 }{3} = \bold{50}type B of nuts

On substituting the value of y in eq. (i), we get

x + 50 = 100

\implies x = 100 - 50

\implies \bold{x =  50}type A of nuts

Thus, 50 kg of each type of nuts were used.

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Answered by Anonymous
0

Answer:

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