Question

A 100 kg shell moving with a velocity of 35 m/s explodes and bursts into two parts, one of mass 30
kg and the other of mass 70 kg. The 30 kg part is brought to rest on explosion. With what velocity does the 70 kg part move?​

Answer 1

Answer:

i have changed the value but not he process . my main objective is that you understand this process and solve it by itself

Explanation:

M=40 kg

M  

1

​  

=15kg;V  

1

​  

=0

V  

D

​  

=72km/h=  

3600

72×1000

​  

=20m/s

M  

2

​  

=M−M  

1

​  

=40−15=25kg

​  

 

P  

i

​  

 = initial momentum= MV  

0

​  

 

P  

i

​  

=40×20=800kgm/s

P  

f

​  

 = final momentum

P  

f

​  

=M  

1

​  

V  

1

​  

+M  

2

​  

V  

2

​  

=15×0+25×V  

2

​  

 

P  

f

​  

=25V  

2

​  

 

P  

f

​  

=P  

i

​  

 

​  

 (momentum conservation)

800=25V  

2

​  

 

V  

2

​  

=  

25

800

​  

=32m/s

Answer 2

Answer:

Come on guys it's easy...

As per the law of conservation of mass:-

M1V1= M2V2

Explanation:

M=100kg

V=35m/s

m1=30kg

v1= 0m/s

m2=70kg

v2= _?_

Soo.....

MV = m1v1 + m2v2

100×35 = 30×0 + 70×v2

100×35/70 = v2

100/2 = v2

50m/s = v2

HERE IS YOUR ANSWER.....

IF YOU LIKE IT PLEASE MARK ME AS A BRAINLIST.