Physics, asked by nareshsharmans634, 6 months ago

A 100 Kw engine is operating between 217 and 17 degree Celsius the efficiency of engine is..?
(A) 25%
(B) 24%
(C)27%
(D) 52%

Answers

Answered by gowdaramyar8
0

Answer:

may be my answer helps you

Explanation:

For a Carnot engine, efficiency e=1−

T

1

T

2

=1−

227+273

127+273

=1−

500

400

=

5

1

Now, e=

Heat input

Work output

=

6×10

4

W

W=e×6×10

4

=

5

1

×6×10

4

=1.2×10

4

cal

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