A 100 m splinter uniformly increases his speed from rest at the rate if 1m/s.find final speed
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The calculation is as follows:
Use equation of motions: SUVAT
s-displacement, u-initial velocity, v-final velocity,a- acceleration, t-time
v=u + atv2 = u2 + 2ass=1/2(u+v)ts=ut + 1/2at2
The first part AB: u= 0m/s
a= 1.5m/s2
s= 75m
therefore time taken s= ut + 1/2at2
75=1/2 x 1.5 x t2
t2= 150/1.5
t2= 100
t= 10s
Therefore time taken in the first part is 10 seconds
Time taken in part 2 BC:
final velocity (v)= 0m/s
displacement (s)= 25m
Initial velocity (u) will be given by the final velocity of the first part:
u-0 s-75 a-1.5m/s2
v2=u2+2as
v2=2x1.5x75
v2= 225
therefore v = 15m/s (this would be the initial velocity for the second part)
time will be given by:
s=1/2(u+v)t
25=1/2(0+15)t
25=15/2t
t= 25x2/15 t =3.333seconds
Time taken in the last part is 3.333 seconds
Use equation of motions: SUVAT
s-displacement, u-initial velocity, v-final velocity,a- acceleration, t-time
v=u + atv2 = u2 + 2ass=1/2(u+v)ts=ut + 1/2at2
The first part AB: u= 0m/s
a= 1.5m/s2
s= 75m
therefore time taken s= ut + 1/2at2
75=1/2 x 1.5 x t2
t2= 150/1.5
t2= 100
t= 10s
Therefore time taken in the first part is 10 seconds
Time taken in part 2 BC:
final velocity (v)= 0m/s
displacement (s)= 25m
Initial velocity (u) will be given by the final velocity of the first part:
u-0 s-75 a-1.5m/s2
v2=u2+2as
v2=2x1.5x75
v2= 225
therefore v = 15m/s (this would be the initial velocity for the second part)
time will be given by:
s=1/2(u+v)t
25=1/2(0+15)t
25=15/2t
t= 25x2/15 t =3.333seconds
Time taken in the last part is 3.333 seconds
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