Question

A 100 metre hollow tube of uniform thickness has two open ends x and y. Ammonia gas is sent into the tube from end x and HCL from end y, simultaneously. At what distance from end x, the gases first meet to form a smoke ring?

Answer 1

Answer:

near ammonia

Explanation:

s

becous hcl got a less mas

Answer 2

Answer:

From Graham's law:

L1/L2=√M1/M2

66.66m