Question

a 100 mH coil carries a current of 1 A. The energy stored in the magnetic fied is ........

Answer 1

The Energy stored in the magnetic Field (E) :




E = Li^2/2


Now,

L = 100 mH = 100 * 10^-3H = 0.1H

i = 1 A

So,

E = 0.1 * (1)^2/2

E = 0.05J of Energy..
Hope it helps..

Answer 2

Answer:

The energy stored in the magnetic field is 50 milli joule.

Explanation:

Given that,

Current I = 1 A

Inductance L =100 mH

We need to calculate the energy stored in the magnetic field

Using formula of energy stored

$E =\dfrac{1}{2}\times LI^2$

Where, L = inductance

I = Current

Put the value in the formula

$E =\dfrac{1}{2}\times100\times10^{-3}\times1^2$

$E =50\times10^{-3}J$

$E =50\ mJ$

Hence, The energy stored in the magnetic field is 50 milli joule.