Chemistry, asked by hydenpaulhyden4458, 1 year ago

A 100 ml solution of 0.1 n hcl was titrated with 0.2n naoh solution.the titration was discontinued after adding 30ml of naoh solution . the remaining the titration was completed by adding 0.25 n koh solution .the volume of koh required for completeting the titration is

Answers

Answered by kobenhavn
21

Answer: The volume of KOH required for completing the titration is 16 ml.

Explanation:

\text{no of gram equivalents}={\text{Normality}\times {\text{Volume in L}}

\text{no of gram equivalents of} HCl=0.1\times 0.1L=0.01gequivalent

HCl+NaOH\rightarrow NaCl+H_2O

\text{no of gram equivalents of} NaOH=0.20\times 0.03=0.006gequivalents

Now gram equivalets left =(0.01-0.006)=0.004gequivalents

0.004=0.25N\times {\text{Volume in L}}

{\text{Volume in L}}=0.016L=16ml

Answered by 18shreya2004mehta
5

Explanation:

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