A 100 ml vessel containing O2 (g) at 1.0 atm and 400 K is connected to a 300 ml vessel containing NO(g) at 1.5 atm and 400 K by means of a narrow tube of negligible volume where gases react to form NO2 . Final pressure of mixture will be –
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Answer:
Volume of O
2
(g)V=100ml
T=400k pressure P=1 atm
n=
RT
PV
millimole
=
0.0821×400
1×100
=3mmole
volume of No = 300ml
T=400kP=1.5atm
n=
0.0821×400
1.5×300
millimole
=13.7mmol
2NO+O
2
→2NO
2
3 millimole react with 6 millimole No
Number of mole = 13.7mol
Final pressure P=
V
nRT
=
400
13.7×0.0821×400
=1.125atm
Explanation:
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