A 100 n force acts horizontally on a block of 10 kg placed on a horizontal rough surface of coefficient of friction = 0.5. If the acceleration due to gravity is taken as 10 ms- 2 , the acceleration of the block ( ms- 2) will be
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A 100 n force acts horizontally on a block of 10 kg placed on a horizontal rough surface of coefficient of friction = 0.5. If the acceleration due to gravity is taken as 10 ms- 2 , the acceleration of the block ( ms- 2) will be
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Answer:
5m/s^2
Explanation:
limiting friction=μmg=0.5×10g=50N
net force =100−50=50N
50=10a
a=5m/s^2
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