Question

A 100 N force applied on a block of mass 50 kg produces a constant velocity of 5 m/min on rough surface. The force of friction exerted on the block will be

1/100N
2/200N
3/300N
4/400N

please give relevant answer with process.​

Answer 1

$\huge{\pink{\underline{\underline{Answer:-}}}}$

Given:

On a block of mass 50 kg,

force applied= 100 N and moves with constant velocity

To find:

Force of friction exerted on block = ?

Solution:

Refer attachment

When a force is applied forward, friction acts backward

As mentioned, block moves with constant velocity which indicates acceleration is zero

F - Fs = ma

100 - Fs = 50 × 0

Mass cannot be zero but on multiplication,

100 = Fs

Fs = 100 N

Required answer:

Thus, force of friction exerted on block is 100N

Basic points:

# Solve more such questions to get a good hold on it

Answer 2

Answer:

It is a very interesting real fact that Force has a value if and only if the force applied on any body is moving with an acceleration i.e the velocity should get increasing. If not Force is simply Zero.

Force = Mass X Acceleration

If Velocity is constant or not changing, then Acceleration is absolute 0

Resulting Force = Zero.

In this case, when the Applied force 100 N was acted on the box, initially the Net force had a value until the box accelerated to 5 m/min (motion) from 0 m/min (rest). Once the box attained the velocity of 5 m/min and became constant, the Net force became Zero.

So, Net Force = Applied Force - Frictional Force

As per above Explanation Net Force becomes 0 as the velocity becomes constant.

0 = Applied Force - Frictional Force

Applied Force = Frictional Force = 100 N

Explanation:

IT MAY HELP YOU