Question

A 100 Ω resistance and a capacitor of 100 Ω reactance are connected in series across a 220 V source. When the capacitor is 50% charged, the peak value of the displacement current is
(1) 2.2 A (2) 11 A
(3) 4.4 A (4) 11√2 A

Answer 1

Answer:

2.2A

Explanation:

Here ,R=100ohm

net impedance,

Z=√R^2+X^2L

peak value of displacement current

=max . conduction current in curicit

= €o/Z =220√2/100√2

=2.2A

Answer 2

Answer:

$\frac{220 \sqrt{2} }{ 100\sqrt{2} } = 2.2$