A 100 V battery is connected across a resistor and causes a current of 5 mA to flow.
Determine the resistance of the resistor. If the voltage is now reduced to 25 V, what will
be the new value of the current flowing?
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resistance =100/5 i.e. 20 k ohm
and
new current = 25/ 20 i.e. 1.25 mA
and
new current = 25/ 20 i.e. 1.25 mA
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