A 100 watt, 110 volt incandescent lamp is connected in series with an electrolyte cell containing cadmium sulphate solution. What weight of cadmium will be deposited by the current flowing for 10 hours?
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SOLUTION :
The reduction of Nitrobenzene can be written as:
C6H5NO2 + 6H+ + 6e-→C6H5NH2 + 2 H2O
Molar mass of Nitrobenzene = 123 g
123 g of nitrobenzene use 6 moles electron for complete reduction.
So 12.3 g of nitobenzene would use = 6/123 x 12.3 = 0.6 mole electrons
Amount of charge in 0.6 mole electron = 0.6 x 96500 = 57900 C
But the efficiency of current is 50 % so it would require twice amount of charge
Therefore the amount of charge required = 57900 x 2 = 115800 C.
The reduction of Nitrobenzene can be written as:
C6H5NO2 + 6H+ + 6e-→C6H5NH2 + 2 H2O
Molar mass of Nitrobenzene = 123 g
123 g of nitrobenzene use 6 moles electron for complete reduction.
So 12.3 g of nitobenzene would use = 6/123 x 12.3 = 0.6 mole electrons
Amount of charge in 0.6 mole electron = 0.6 x 96500 = 57900 C
But the efficiency of current is 50 % so it would require twice amount of charge
Therefore the amount of charge required = 57900 x 2 = 115800 C.
Answered by
0
Answer:
19.06g
Explanation: w=ItE/96500
E(cd)=112.4/2(atomic mass is 112.4)
Substitute other values.
W=19.06g
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