Chemistry, asked by akshayrcb4, 5 hours ago

A 100 watt bulb emits monochromatic light of wavelength
900 nm. The number of photons emitted per second by the
bulb (1 watt = 1 Is='). (n = 6.625 x 10-34 Js)​

Answers

Answered by NewGeneEinstein
2

Answer:-

  • Power of bulb=100w=100Js^{-1}
  • Wavelength=900nm

We know that

\boxed{\sf Power=\dfrac{Energy}{Time}}

\boxed{\sf Energy \:of\:Photon(E)=hv}

\\ \sf\longmapsto E=\dfrac{hc}{\lambda}

\\ \sf\longmapsto E=\dfrac{6.626\times 10^{-34}Js\times 3\times 10^8ms^{-1}}{900\times 10^{-9}m}

\\ \sf\longmapsto E=0.02208\times 10^{-17}J

\\ \sf\longmapsto E=2.208\times 10^{-19}J

Now

\boxed{\sf Number\:of\:photons\:emitted=\dfrac{Power\:of\:the\:bulb}{Energy\:of\:one\:photon}}

\\ \sf\longmapsto Number\:of\;photons\:emitted=\dfrac{100Js^{-1}}{2.208\times 10^{-19}J}

\\ \sf\longmapsto Number\:of\;photons\:emitted=45.28\times 10^{19}s^{-1}

\\ \sf\longmapsto Number\:of\;photons\:emitted=4.528\times 10^{20}Per\:second

\\ \\ \underline{\boxed{\bf{\therefore Number\:of\:photons\:emitted=4.528\times 10^{20}Photons/second}}}

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