Question

A 100 watt bulb emits wavelength of 400nm. Calculate the no. Of photons emits per second

Answer 1

. ∴ E=x×hcλ Given: E=100J h=6.626×10−34Js c=3×108msec−1 λ=400××10−9m Putting these values in Eqn. (i) we get 100=x×6.626×10−34×3×108400×10−9 x=100×400×10−96.626×10−34×3×108photons =2.012×1020photons

Answer 2

Answer:

Explanation:

Please refer the below attachment.