Physics, asked by amusridhar631, 1 year ago

A 100 watt electric bulb is lighted for 3 hrs daily and four 60 watt electric bulbs are lighted for 2h daily.Calculate the units of energy consumed in a month of 30 days.

Answers

Answered by venky2404
5

Answer :

1. For 100W bulb

Electrical energy = Power x Time

=> 100W x 3h

=> 100/1000 kW x 3h

=> 0.1kW x 3h = 0.3kWh daily

=> 0.3kWh x 30 = 9kWh for 30 days

Therefore, 100W bulb = 9kWh....(1)

2. For one 60W bulb

Electrical energy = Power x Time

=> 60W x 2h

=> 60/1000kW x 2h = 0.12kWh daily

Therefore, four bulbs = 0.48kWh

=> 0.48kWh x 30 = 14.4kWh..... (2)

Total energy in a month = (1) + (2)

=> 9kWh + 14.4kWh = 23.4kWh

Therefore, the total energy consumed in a month is 23.4kWh or 23.4 units of energy.

Answered by ujjwal26200
0

Answer:

Answer :

1. For 100W bulb

Electrical energy = Power x Time

=> 100W x 3h

=> 100/1000 kW x 3h

=> 0.1kW x 3h = 0.3kWh daily

=> 0.3kWh x 30 = 9kWh for 30 days

Therefore, 100W bulb = 9kWh....(1)

2. For one 60W bulb

Electrical energy = Power x Time

=> 60W x 2h

=> 60/1000kW x 2h = 0.12kWh daily

Therefore, four bulbs = 0.48kWh

=> 0.48kWh x 30 = 14.4kWh..... (2)

Total energy in a month = (1) + (2)

=> 9kWh + 14.4kWh = 23.4kWh

Therefore, the total energy consumed in a month is 23.4kWh or 23.4 units of energy.

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