Question

a 100 watt heater is used to heat 500g of water for 5 min.what is change in temperature if specific heat of
is 4.2j/gc?​

Answer 1

Answer:

Power = 100 w

Weight of water = 500 g

Time = 5 min

specific heat = 4.2 J/ gc

use formula

p × t = m*s*δ t

(100 × 5 × 60) j = 500 g × 4.2 j /gc δ t

δ t = (60 / 4.2 ) calories

δ t = ( 60 / 4.2 ) × 4.2 joule

δ t = 60°

thanks

Answer 2

From the given question the correct answer is :

The change in temperature if specific heat of

is 4.2j/gc is δ t = 60°

Power = 100 w

Weight of water = 500 g

Time = 5 min

specific heat = 4.2 J/ gc

use formula

p × t = m*s*δ t

(100 × 5 × 60) j = 500 g × 4.2 j /gc δ t

δ t = (60 / 4.2 ) calories

δ t = ( 60 / 4.2 ) × 4.2 joule

δ t = 60°