Question

A 1000 kg car is moving with a speed of 20 m/s is brought to rest in a distance of 15m, the unbalanced force acting on the car in Newtons will be​

Answer 1

2as=v^2-u^2

or,s= v^2-u^2 / 2a

or,a= -(20)^2 / 2×15

or, a= -400/30

or, a= -40/3

therefore, F= m.a

or, F= 1000×40/3

or, F=( 10)^4 × 4/3

or, F= 1.3333 × 10000

or, F= 13333 N