Question

A 1000 kg lift is tied with metallic wire of maximum safe stress of 1.4 × 108
Nm–2
. Calculate the minimum diameter of wire required to move the lift with
maximum acceleration 1.2 m/s2
.

Answer 1

stress=F/A

=>11200N/πr^2

$1.4 \times {10}^{8} = \frac{11200}{\pi {r}^{2} }$

r=198.16

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