A 1000 kg lift is tied with metallic wire of maximum safe stress of 1.4 × 10^8 Nm . calculate the minimum diameter of wire required to move the lift with maximum acceleration 1.2 m/s^2 ....
Answers
Answered by
4
F=MASS × ACCELERATION
= 1000×1.2
= 1.2 × 10^3N
stress= F/A
1.4 × 10^8= 1.2 × 10^3/A
from here on calculate the area and then diameter
= 1000×1.2
= 1.2 × 10^3N
stress= F/A
1.4 × 10^8= 1.2 × 10^3/A
from here on calculate the area and then diameter
Similar questions