A 1000 kg truck is parked on a bridge 100 m long at a distance of 25 m from one end of the bridge. The mass of the bridge is 200 kg m−1. Calculate the reaction forces at the supports at the two ends of the bridge. (Take g = 10 ms−2)
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As mass =1000
we know that force = mgh
then 1000×10×h= 10000h
h= height is unknown then
pressure = froce /area
then 10000/2500
= 4h pascal
we know that force = mgh
then 1000×10×h= 10000h
h= height is unknown then
pressure = froce /area
then 10000/2500
= 4h pascal
Answered by
11
Answer:
R1 - 10750 kgs, R2 - 10250 Kgs
Explanation:
ΣFx=0: Produces nothing as no force in x direction
ΣFy=0: 1000 + 20000 - R1 - R2 = 0
∴ R1 + R2 = 21000 -- (1)
ΣM=0: Taking moment at point R1
∴ 1000 x 25 + 20000 x 50 - R2 x 100 = 0
R2 = (25000 + 10,00,000)/100
R2 = 10250 Kgs
Substituting in (1) we get,
R1 = 21000 - 10250 = 10750 kgs
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