A 1000 kg vehicle moving with a speed of 20 m/s is
brought to rest in a distance of 50 metres :
(1) Find the acceleration.
(2) Calculate the unbalanced force acting on the vehicle.
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♧Question ♧
A 1000 kg vehicle moving with a speed of 20 m/s is
brought to rest in a distance of 50 metres :
(1) Find the acceleration.
(2) Calculate the unbalanced force acting on the vehicle.
☆☆Answer ☆☆
- M=1000 kg(mass)
- u=20m/s(initial position)
- v=0m/s(final position)
- s=50m(distance)
♡using newton's second equation of motion
(i)V²=u²+2as
0²=(20)²+2×a×50
0²=400+50a
-400=50a
a=-400/50
a=-4
(ii) we know that unbalanced force equal to mass × acceleration .
so, f=m×a
=>f=1000×-4
=>f=-4000N
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