Question

A 1000 KG VEHICLE MOVING WITH A SPEED OF 20M/S IS BROUGHT TO REST IN A DISTANCE OF 50METRES FIND ITS ACCELERARION

Answer 1

mass = m = 1000kg

initial speed = u = 20m/s

final speed = v = 0m/s

distance = s = 50m

acceleration = a = ?

Force = F = ?
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v²-u² = 2as

(0)²-(20)² = 2(a)(50)

0-400 = 100a

-400/100 = a

-4m/s² = a
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F = ma

F = 1000kg × -4m/s²

F = -4000kgm/s²

F = -4000N

F = -4KN

(here minus sign shows the force acting opposite direction on it )
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so acceleration is -4m/s²

and force acting on it is -4000 newton or -4 kilo newton
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