Question

A 1000 kg vehicles moving with a speed of 10 metre per second is brought to rest in distance of 50 by the application of brakes calculate its acceleration​

Answer 1

Heya!

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♦Given that =>

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➰Mass M = 1000 kg

➰Initial Velocity u = 10m/s

➰Final Velocity v = 0

➰Distance s = 50 m

♦Using the Third Equation of Motion ,

V² - U² = 2as

(0)² - (10)² = 2 × a × 50

=> 100 = 100a

=> Acceleration a = 1 m/s²

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♦Force F = Mass M × acceleration a

=> F = 1000 × 1

=> F = 1000 N

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Answer 2

Answer:

F=1000 N................