Question

A 1000 N block is placed on an inclined plane with angle of 300. The components of the weight
parallel & perpendicular to the inclined plane , respectively , are

Answer 1

Explanation:

1000/300

10/3

this is the answer

Answer 2

Given info : A 1000 N block is placed on an inclined plane with angle of 30°.

To find : The components of the weight

parallel & perpendicular to the inclined plane , respectively , are

solution : draw free body diagram of system.

weight body is directed vertically downwards.

so the component of weight along plane (or parallel to the plane) , W = 1000 sin30° = 1000 × 1/2 = 500 N

the component of weight perpendicular to the plane , W' = 1000cos30° = 1000 × √3/2 = 500√3 N

Therefore the components of weight parallel and perpendicular to the inclined plane are 500 N and 500√3 N respectively.

also read similar questions : A block of weight of 1N rests on an inclined plane of inclination θ with the horizontal. The coefficient of friction...

https://brainly.in/question/38558075

A block of mass 2 kg placed on an inclined plane just slides down when its angle inclination is 45° calculate the

(i) c...

https://brainly.in/question/9149483