Question

a 1000 watt radio transmitter operates at frequency of 880 kilocycle/sec .how many photons per second does it emit?

Answer 1

1000 W = 1 KW

1 KW = 1000 J / second.

Energy of a single photon = Planck's constant * Frequency of photon

Suppose ' x ' number of photons are emitted per second. Then we cay say that,

Energy = x * Planck's constant * Frequency

=> x = Energy ( Power ) / Planck's constant * Frequency

=> x = 1000 / 6.62 * 10⁻³⁴ * 880,000 Hz

=> x = 1.88 * 10³⁰ Photons per second

Hence solved !

Answer 2

1000 W = 1 KW

1 KW = 1000 J / second.

Energy of a single photon = Planck's constant * Frequency of photon

Suppose ' x ' number of photons are emitted per second. Then we cay say that,

Energy = x * Planck's constant * Frequency

=> x = Energy ( Power ) / Planck's constant * Frequency

=> x = 1000 / 6.62 * 10⁻³⁴ * 880,000 Hz

=> x = 1.88 * 10³⁰ Photons per second