a 1000 watt radio transmitter operates at frequency of 880 kilocycle/sec .how many photons per second does it emit?
Answers
Answered by
55
1000 W = 1 KW
1 KW = 1000 J / second.
Energy of a single photon = Planck's constant * Frequency of photon
Suppose ' x ' number of photons are emitted per second. Then we cay say that,
Energy = x * Planck's constant * Frequency
=> x = Energy ( Power ) / Planck's constant * Frequency
=> x = 1000 / 6.62 * 10⁻³⁴ * 880,000 Hz
=> x = 1.88 * 10³⁰ Photons per second
Hence solved !
Answered by
0
1000 W = 1 KW
1 KW = 1000 J / second.
Energy of a single photon = Planck's constant * Frequency of photon
Suppose ' x ' number of photons are emitted per second. Then we cay say that,
Energy = x * Planck's constant * Frequency
=> x = Energy ( Power ) / Planck's constant * Frequency
=> x = 1000 / 6.62 * 10⁻³⁴ * 880,000 Hz
=> x = 1.88 * 10³⁰ Photons per second
Similar questions