Question

A 1000kg vehicle moving with a speed of 20m/s is brought to rest in a distance of 50m.find the acceleration

Answer 1

Answer:

Given,

Initial velocity(u)=20ms

−1

Final velocity(v)=0

Distance moved(S)=50m

We know,

v

2

=u

2

+2aS

0=20

2

+2a×50

−400=100a

a=

100

−400

a=−4ms

−2

Now,

F=ma

F=1000×−4

=−4000N