Question

A 1000ml sample of gas at -73°c and 2 atm is heated 120°c and pressure is reduced to 0.5atm. what will be the final volume​

Answer 1

Answer:

7.86 L

Explanation:

Given,

Initial Temperature, $T_{1}$ = -73$^0C$ = 200 K

Initial Pressure, $P_{1}$ = 2 atm

Initial Volume, $V_{1}$ = 1000mL

Final Temperature, T' = 120$^0C$ = 393 K

Final Pressure, P' = 0.5 atm

Final Volume, V' = ?

Here we can use the combined gas law,

$\frac{P_{1}V_{1} }{T_{1} } = \frac{P'V'}{T'}$

We have to find V'. So changing the equation,

$V' = \frac{P_{1}V_{1} }{T_{1} } . \frac{T'}{P'}$

Substituting the given values,

$V' = \frac{2. 1000 }{200 } . \frac{393}{0.5}$

= $10 . \frac{3930}{5}$

= 7860 mL

= 7.86 L